Suppose that in addition to being sorted, the entries of A are distinct integers. Design an efficient algorithm for finding an index i such that A[i]=i or indicating that no such index exists. 

We can apply binary search technique for this too as we are aware that array is sorted and have distinct elements.

Below is the working code in C

#include<stdio.h>
int bsearch(int a[],int size)
{
    int low=0;
    int up=size-1;
    int mid;
    while(low <= up) {
        mid=(low+up)/2;
        if(a[mid]==mid)
            return mid;
        else if(a[mid]<mid)
            low = mid+1;
        else
            up = mid-1;
    }
    return -1;
}
int main()
{
    int arr[10]={-1,0,2,4,6,8,10,12,14,15};
    int pos;
    pos=bsearch(arr,10);
    if(pos == -1)
        printf("element for a[i] == i is not found\n");
    else
        printf("element for a[i] == i is at location %d\n",pos+1);
    return 0;
}
 

Write a program that takes a sorted array A and a key elem and returns the index of first occurance of key in A, and returns -1 if key doesnot appears in A.

Above problem can be solved by doing simple modification of binary search program. Below is the working code in C.

#include<stdio.h>
int bsearch(int a[],int size,int elem)
{
        int low=0;
        int up=size-1;
        int mid;
        while(low <= up) {
                mid=(low+up)/2;
                if(a[mid]==elem)
                {       if(a[mid-1] == elem)
                                up=mid-1;
                        else
                                return mid;
                }
                else if(a[mid]<elem)
                        low=mid+1;
                else
                        up=mid-1;
        }
        return -1;
}
int main()
{
        int arr[10]={1,3,3,3,3,6,9,9,9,10};
        int pos,srch_elem;
        printf("Enter element to search : ");
        scanf("%d",&srch_elem);
        pos=bsearch(arr,10,srch_elem);
        if(pos == -1)
                printf("%d is not in array\n",srch_elem);
        else
                printf("first occurance of %d is at location %d\n",srch_elem,pos+1);
        return 0;
}